For all complex numbers z1,z2 satisfying |z1|=12 and |z2−3−4i|=5, the minimum value of |z1−z2| is
A
0
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B
2
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C
7
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D
17
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Solution
The correct option is B2 The first is a circle with center at (0,0) and radius 12. The second is a circle with center at (3,4) and radius 5 which passes through the origin (since √32+42=5) The minimum value can be seen from the diagram as 2. Hence, (b) is correct.