For all complex numbers z1,z2 satisfying |z1|=12;|z2−3−4i|=5, the minimum value of |z1−z2| is
A
0
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B
2
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C
7
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D
17
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Solution
The correct option is B2 The two circles are C1(0,0),r1=12;C2(3,4),r2=5 and it passes through origin.
The distance between centres is C1C2=√32+42<7=r1−r2 Hence, circle C2 lies inside circle C1. Therefore, the minimum distance between them is AB=C1B−C1A=r1−2r2=12−10=2