For all complex numbers z1,z2 satisfying |z1|=12 and |z2−3−4i|=5, the minimum value of |z1−z2| is
A
2
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B
7
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C
17
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Solution
The correct option is A 2 |z1−z2|=|z1−(z2−3−4i)−(3+4i)|≥|z1|−|z2−3−4i|−|3+4i|≥12−5−5[using|z1−z2|≥|z1|−|z2|] Alternate Solution Clearly from the figure |z1−z2| is minimum when z1,z2 lie along the diameter.