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Question

For all complex numbers z1, z2 satisfying |z1|=12 and |z2−3−4i|=5, the minimum value of |z1−z2| is


A

0

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B

2

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C

7

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D

17

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Solution

The correct option is B

2


Given : |z1|=12. It is a circle with centre at O(0,0) and radius, OB=12

Also, |z234i|=5, so, it is a circle with centre at C(3,4) and radius =5

OD=2×5=10

|z1z2|min=BD=OBOD

=1210

=2


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