For all complex numbers z1, z2 satisfying |z1|=12 and |z2−3−4i|=5, the minimum value of |z1−z2| is
2
Given : |z1|=12. It is a circle with centre at O(0,0) and radius, OB=12
Also, |z2−3−4i|=5, so, it is a circle with centre at C(3,4) and radius =5
⇒OD=2×5=10
|z1−z2|min=BD=OB–OD
=12−10
=2