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For all posit...

Question

For all positive integral values of n, $3^{2 n}$ - 2n + 1 is

divisible by

A

2

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B

4

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C

8

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D

12

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Solution

The correct option is A
2

Putting n = 2 in $3^{2 n}$ - 2n + 1 then,

$3^{2 \times 2}$ - 2×2+1 = 81 - 4 + 1 = 78, which is divisible

by 2.

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