Question

For an adiabatic expansion of a mono atomic perfect gas, the volume increase by 24%. What is the percentage decrease in pressure?

• A. 24%
• B. 40%
• C. 48%
• D. 71%

Answer 1

Answer: (B)

40%

$p{V}^{\gamma }=const\Rightarrow V^{\gamma }\frac{\Delta p}{p}=p\gamma V^{\gamma -1}\frac{\Delta V}{V}\Rightarrow \frac{\Delta p}{p}=\gamma \frac{\Delta V}{V}=\frac{5}{3}\times 24=40$