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Question

For an electron, with n = 3 has only one radial node. The orbital angular momentum of the electron will be

A
0.0
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B
6h2π
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C
2h2π
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D
3(h2π)
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Solution

The correct option is C 2h2π
Number of radial nodes = n - l - 1 = 1, n = 3.
l=1.
Orbital angular momentum =l(l+1)h2π
=2h2π

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