Question

For an electron, with n = 3 has only one radial node. The orbital angular momentum of the electron will be

• A. \N
• B. $\sqrt{6}\frac{h}{2\pi }$
• C. $\sqrt{2}\frac{h}{2\pi }$
• D. $3\left(\frac{h}{2\pi }\right)$

Answer 1

The correct option is C $\sqrt{2}\frac{h}{2\pi }$

Number of radial nodes = n - l - 1 = 1, n = 3.
$\therefore l=1.$
Orbital angular momentum $=\sqrt{l(l+1)}\frac{h}{2\pi }$
$=\sqrt{2}\frac{h}{2\pi }$