You visited us 2 times! Enjoying our articles? Unlock Full Access!

Enthalpy

For an endoth...

Question

For an endothermic reaction, the correct statement about the energy of activation for forward and backward reaction is:

E_{a_{f}} > E_{a_{b}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

E_{a_{f}} < E_{a_{b}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

E_{a_{f}} = E_{a_{b}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $E_{a_{f}} > E_{a_{b}}$
As we know,
For endothermic reaction, $Δ H = + v e$
and $Δ H = E_{a_{f}} - E_{a_{b}}$ .

$∴ E_{a_{f}} > E_{a_{b}}$

Suggest Corrections

Similar questions

E_{a} (f)

E_{a} (b)

Δ E

A + B ⇌ 2 C + D

2 (E_{a})_{f} = (E_{a})_{b}; (E_{a})_{f}

(E_{a})_{b}

(E_{a f})

80 k J / m o l

Δ H = - 40 k J / m o l

E_{a f}

20 k J / m o l

(E_{a f})

80 k J . m o l^{- 1} .

Δ H = - 40 k J . m o l^{- 1}

E_{a f}

20 k J . m o l^{- 1} .

(E_{a f})

80 {kJ mol}^{- 1}

Δ H = - 40 {kJ mol}^{- 1}

E_{a f}

20 {kJ mol}^{- 1}

Join BYJU'S Learning Program