For an ideal gas reaction 2 A - B - C - Dvalue of K p will be -A- K p - n C n D - n A 2 n B - RT - V B- K p - n C n D - n A 2 n B - V - RT C- K p - n C n D - n A n B - V - RT 2D - K p - n C n D - n A 2 n B - V 2- RT

Name: NEET - Grade 11 - Chemistry - Chemical Equilibrium - Session 05 - D07
Uploaded: 2022-07-04T10:36:42+05:30
Description: The correct option is B K_p =n_C n_D n_A^2n_B× nbsp; (VRT) nbsp;2A + B ⇌ C + D We know that, K_P = K_c (RT)^ n nbsp; nbsp; nbsp; nbsp; ...(1) he ...

The correct option is B K_p =n_C n_D n_A^2n_B× nbsp; (VRT) nbsp;2A + B ⇌ C + D We know that, K_P = K_c (RT)^ n nbsp; nbsp; nbsp; nbsp; ...(1) he ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Derivation of Kp and Kc

For an ideal ...

Question

For an ideal gas reaction
$2 A + B ⇌ C + D$
value of $K_{p}$ will be :

K_{p} = \frac{n_{C} n_{D}}{n_{A} n_{B}} \times (\frac{V}{R T^{2}})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K_{p} = \frac{n_{C} n_{D}}{n_{A}^{2} n_{B}} \times (\frac{V^{2}}{R T})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K_{p} = \frac{n_{C} n_{D}}{n_{A}^{2} n_{B}} \times (\frac{R T}{V})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K_{p} = \frac{n_{C} n_{D}}{n_{A}^{2} n_{B}} \times (\frac{V}{R T})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $K_{p} = \frac{n_{C} n_{D}}{n_{A}^{2} n_{B}} \times (\frac{V}{R T})$
$2 A + B ⇌ C + D$
We know that, $K_{P} = K_{c} (R T)^{△ n}$ ...(1)
here, $K_{c} = \frac{[C] [D]}{[A]^{2} [B]}$
$K_{c} = \frac{\frac{n_{C}}{V} \times \frac{n_{D}}{V}}{\frac{n_{A}^{2}}{V^{2}} \times \frac{n_{B}}{V}}$
$K_{c} = (\frac{n_{C} n_{D}}{n_{A}^{2} n_{B}} \times V)$
$△ n = 2 - 3 = - 1$
Putting value of $K_{c}$ and $△ n$ in eqn. (1)
$K_{p} = [\frac{n_{C} n_{A}}{n_{A}^{2} n_{B}} V] \times (R T)^{△ n}$
$= (\frac{n_{C} n_{D}}{n_{A}^{2} n_{B}}) V \times (R T)^{- 1}$
$K_{P} = \frac{n_{C} n_{D}}{n_{A}^{2} n_{B}} \times (\frac{V}{R T})$

Suggest Corrections

Similar questions

Q. For an ideal gas reaction

2 A + B ⇌ C + D

value of

K_{p}

will be :

Q. For the reaction

C O (g) + C l_{2} (g) ⇌ C O C l_{2} (g)

the value of

\frac{K_{p}}{K_{c}}

is equal to :

Q. Assertion :

K_{p} = K_{c}

for all reactions. BECAUSE Reason:

K_{p}

and

K_{c}

are interrelated by the equation

K_{p} = K_{c} {(R T)}^{Δ n}

For a general reaction aA(g) + bB(g) $⇋$ cC(g)+ dD(g), what is the relationship between the equilibrium constants $K_{c}$ and $K_{p}$ ? [assume $Δ$ n = $μ$ = (c + d) - (a+b) ]\)

Q. The ratio of

K_{p} / K_{c}

for the reaction,

C O (g) + \frac{1}{2} O_{2} (g) ⇌ C O_{2} (g)

Join BYJU'S Learning Program

Explore more

Derivation of Kp and Kc

Standard XII Chemistry

Join BYJU'S Learning Program

For an ideal gas reaction 2A+B⇌C+D value of Kp will be :

The correct option is D Kp=nCnDn2AnB×(VRT) 2A+B⇌C+D We know that, KP=Kc(RT)△n ...(1) here, Kc=[C][D][A]2[B] Kc=nCV×nDVn2AV2×nBV Kc=(nCnDn2AnB×V) △n=2−3=−1 Putting value of Kc and △n in eqn. (1) Kp=[nCnAn2AnBV]×(RT)△n =(nCnDn2AnB)V×(RT)−1 KP=nCnDn2AnB×(VRT)

For an ideal gas reaction
$2 A + B ⇌ C + D$
value of $K_{p}$ will be :