For an ideal gas the value of - E- V T is-

The correct option is A zeroAt some temperature, kinetic energy per mole =3/2RT .So it will depend on temp only,and if we differentiate wrt to T than, ...

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Standard XII

Chemistry

Thermodynamic Processes

For an ideal ...

Question

For an ideal gas the value of ${(\frac{\partial E}{\partial V})}_{T}$ is:

positive

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zero

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negative

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interchangeable

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Solution

The correct option is A zero
At some temperature, kinetic energy per mole $= \frac{3}{2} R T$ .
So it will depend on temp only,
and if we differentiate wrt to T than,
${(\frac{\partial E}{\partial V})}_{T} = 0$

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For an ideal gas the value of (∂E∂V)T is:

The correct option is A zeroAt some temperature, kinetic energy per mole =32RT.So it will depend on temp only,and if we differentiate wrt to T than,(∂E∂V)T=0

For an ideal gas the value of ${(\frac{\partial E}{\partial V})}_{T}$ is:

The correct option is A zero
At some temperature, kinetic energy per mole $= \frac{3}{2} R T$ .
So it will depend on temp only,
and if we differentiate wrt to T than,
${(\frac{\partial E}{\partial V})}_{T} = 0$