Question

For an ideal gas the value of ${\left(\frac{\partial E}{\partial V}\right)}_T$ is:

Answer 1

At some temperature, kinetic energy per mole $=\frac{3}{2}RT$.
So, it will depend on temperature only,
and if we differentiate wrt to $V$ then,
${\left(\frac{\partial E}{\partial V}\right)}_T=0$