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Standard XII

Physics

Relative Velocity in 2D

For an object...

Question

For an object thrown at $45^{o}$ to horizontal, the maximum height ( $H$ ) and horizontal range ( $R$ ) are related are

R = 16 H

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R = 8 H

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R = 4 H

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R = 2 H

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Solution

The correct option is D $R = 4 H$
Here, angle of projection θ=45o
Maximum height H=u2sin2θ2g
Horizontal range R=u2sin2θg
For θ=45o
H=u2sin245o2g=u24g(∵sin45o=12√)
R=u2sin90og=u2g(∵sin90o=1)
∴RH=u2g×4gu2=4
or R=4H

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For an object thrown at 45o to horizontal, the maximum height (H) and horizontal range (R) are related are

For an object thrown at $45^{o}$ to horizontal, the maximum height ( $H$ ) and horizontal range ( $R$ ) are related are