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Question

for any positive integer n, prove that;7n3n divisible by 4.

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Solution

Let P(n):7n3n=4d, where dN
For n=1
LHS = 73
=4×1
=RHS
P(n) is true for n=1.
Assume P(k) is true.
P(k):7k3k=4m, where mN
We wiil prove that P(k+1) is true.
LHS=7k+13k+1
=7k.73k.3
=7.(4m+3k)3.3k
=7×4m+7×3k3.3k
=7×4m+3k(4)
=4(7m+3k)
=4r where r=7m+3k is a natural number.
Therefore, P(k+1) is true whenever P(k) is true.
Therefore, by the principle of mathematical induction, P(n) is true for n, where n is a natural number.

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