wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For any quadratic function y=x2+2x3,y>0

A
xR(0}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
xϕ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
xR
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B xϕ
Given the quadratic equation y=x2+2x3
Now, comparing the equation with y=ax2+bx+c, we get:
a=1;b=2;c=3
We have a=1<0
This means the graph is a downward opening parabola.
Also, Discriminant D=b24ac
D=224×1×3D=412=8<0

Thus, the function has a<0 as well as D<0.
So, we can plot the function as:

Thus, xR,y<0
Or y>0 xϕ

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Graphs of Quadratic Equation for different values of D when a<0
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon