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Byju's Answer
Standard XII
Mathematics
n(A∪B∪C) = n(A) + n(B) + n(C) − n(A∩B) − n(B∩C) − n(C∩A) + n(A∩B∩C)
For any three...
Question
For any three sets
A
,
B
&
C
,
n
(
A
∪
B
∪
C
)
=
n
(
A
)
+
n
(
B
)
+
n
(
C
)
−
n
(
A
∩
B
)
−
n
(
B
∩
C
)
−
n
(
C
∩
A
)
+
n
(
A
∩
B
∩
C
)
A
False
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B
True
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Solution
The correct option is
B
True
Suggest Corrections
0
Similar questions
Q.
For any three sets
A
,
B
&
C
,
n
(
A
∪
B
∪
C
)
=
n
(
A
)
+
n
(
B
)
+
n
(
C
)
−
n
(
A
∩
B
)
−
n
(
B
∩
C
)
−
n
(
C
∩
A
)
+
n
(
A
∩
B
∩
C
)
Q.
Verify n(A
∪
B
∪
C) = n(A) + n(B) + n(C) – n(A
∩
B) – n(B
∩
C) – n(A
∩
C) + n(A
∩
B
∪
C) for the following sets. A = {a, c, e, f, h}, B = {c, d, e, f} and C = {a, b, c, f}
Q.
Verify
n
(
A
∪
B
∪
C
)
=
n
(
A
)
+
n
(
B
)
+
n
(
c
)
−
n
(
A
∩
B
)
−
n
(
B
∩
C
)
−
n
(
A
∩
C
)
+
n
(
A
∩
B
∩
C
)
for the sets given below:
(i) A={4,5,6}, B={5,6,7,8} and C={6,7,8,9}
(ii) A={a, b, c, d, e}, B={x, y, z} and C={a, e, x}
Q.
Observe the figure 1.18 and verify the following equations.
n (A
∪
B
∪
C) = n (A) + n (B) + n (C) − n (A
∩
B ) − n (B
∩
C) − n (C
∩
A) + n (A
∩
B
∩
C)
figure
Q.
Let
A
,
B
,
C
be finite sets. Suppose that
n
(
A
)
=
10
,
n
(
B
)
=
15
,
n
(
C
)
=
20
,
n
(
A
∩
B
)
=
8
and
n
(
B
∩
C
)
=
9
. Then the maximum possible value of
n
(
A
∪
B
∪
C
)
is
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n(A∪B∪C) = n(A) + n(B) + n(C) − n(A∩B) − n(B∩C) − n(C∩A) + n(A∩B∩C)
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n(A∪B∪C) = n(A) + n(B) + n(C) − n(A∩B) − n(B∩C) − n(C∩A) + n(A∩B∩C)
Standard XII Mathematics
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