Question

For $C{r}^{+}$ ion, how many electrons can have n + l + | m | =4, with clockwise spin?

Answer 1

The electronic configuration for $C{r}^{+}$ is
$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^5$
now For the orbital $2p$
$n=2,l=1,m=+1$
$n=2,l=1,m=-1$ and
for the orbital $3p$
$n=3,l=1,m=0$
These are the only possible combination of quantum numbers which can give $n+l+|m|=4$