For Cu(s)+NO3(aq)+H+(aq)→Cu2+(aq)+NO2(g)+xH2O(l), when the equation is balanced what is the coefficient of H+?
A
1
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B
2
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C
3
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D
4
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E
5
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Solution
The correct option is D 4 The unbalanced chemical equation is Cu(s)+NO−3(aq)+H+(aq)→Cu2+(aq)+NO2(g)+H2O(l) All atoms except H and O are balanced. Assign oxidation numbers. Cu(s)0+N+5O−3(aq)+H+(aq)→Cu2++2(aq)+N+4O2(g)+H2O(l) The oxidation number of Cu increases from 0 to +2. Total increase in the oxidation number is 2. The oxidation number of N decreases from +5 to +4. Total decrease in the oxidation number is 1. Balance increase in oxidation number with decrease in oxidation number by using appropriate coefficients. Cu(s)+2NO−3(aq)+H+(aq)→Cu2+(aq)+2NO2(g)+H2O(l) Balance O atoms by adding one water molecule on products side. Cu(s)+2NO−3(aq)+H+(aq)→Cu2+(aq)+2NO2(g)+2H2O(l) Balance H atoms by adding 3 protons to reactant side. Cu(s)+2NO−3(aq)+4H+(aq)→Cu2+(aq)+2NO2(g)+2H2O(l) This is balanced chemical equation. The coefficient of H+ ions is 4.