You visited us 1 times! Enjoying our articles? Unlock Full Access!

Balancing Redox Equations

For decolouri...

Question

For decolourization of 1 mole of $K M n O_{4}$ , the moles of $H_{2} O_{2}$ required is

\frac{1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{3}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{5}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{7}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{5}{2}$
$2 K M n O_{4} + 3 H_{2} S O_{4} \to K_{2} S O_{4} + 2 M n S O_{4} + 3 H_{2} O + 5 O$
$\frac{5 H_{2} O_{2} + 5 O \to 5 H_{2} + 5 O_{2}}{2 K M n O_{4} + 3 H_{2} S O_{4} + 5 H_{2} O_{2} \to K_{2} S O_{4} + 2 M n S O_{4} + 8 H_{2} O + 5 O_{2}}$

Suggest Corrections

Similar questions

K M n O_{4}

H_{2} O_{2}

K M n O_{4}

H_{2} O_{2}

1 m o l e

K M n O_{4}

H_{2} O_{2}

K M n O_{4}

H_{2} O_{2}

K M n O_{4}

H_{2} O_{2}

Join BYJU'S Learning Program