For nϵN, the value of the definite integral ∫nπ+V0√1+cos2x2dx where π2<V<π is
A
2n+1−cosV
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B
2n−sinV
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C
2n+2−sinV
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D
2n+1−sinV
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Solution
The correct option is C2n+2−sinV Given, ∫nx+v0√2cos2x2dx=∫nx+v0|cosx|dx ∫nx0|cosx|dx+∫nx+v0|cosx|dx n∫n0|cosx|dx+∫v0|cosx|dx 2n+∫n/20cosxdx−∫vn/2cosxdx=2n+2−sinv