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Standard XII

Chemistry

Positive Rays and Neutrons

For emission ...

Question

For emission of $α$ -particle from uranium nucleus, shortage of two electrons in thorium is due to :
$_{92} U^{235} -_{2} H e^{4} \to_{90} T h^{231}$

conversion of electron to positron

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adsorption in the nucleus

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annihilation

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combination with positron to evolve energy

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Solution

The correct options are
C combination with positron to evolve energy
D annihilation
For emission of $α$ -particle from uranium nucleus :
$_{92} U^{235} -_{2} H e^{4} \to_{90} T h^{231}$
Shortage of two electrons in thorium is due to Annihilation. Electron combine with positron to evolve energy.
$_{0}^{- 1} e +_{0}^{+ 1} e \to e n e r g y$

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Similar questions

Q. Let us consider emission of

α

-particle from uranium nucleus:

_{92} U^{235} \to_{2} {H e}^{4} \to

_{90} {T h}^{231}

e = 92

e = 0

e = 90

p = 92

p = 2

p = 90

n = 143

n = 2

n = 141

Shortage of two electrons in thorium is due to:

Thorium (90) formed from emission of

α

-particle from uranium (92, group IIIB) has been placed in group IIIB.

Q. In successive emission of α and β-particles, the number of α and β-particles should be emitted for the conversion of

_{92} U^{238}

_{82} P b^{206}

are:

Q. For the β+(positron) emission from a nucleus, there is anothercompeting process known as electron capture (electron from an innerorbit, say, the K–shell, is captured by the nucleus and a neutrino isemitted).1A A e X Y Z Z ν++ → + −Show that if β+emission is energetically allowed, electron captureis necessarily allowed but not vice–versa.

For the (positron) emission from a nucleus, there is another competing process known as electron capture (electron from an inner orbit, say, the K−shell, is captured by the nucleus and a neutrino is emitted).

Show that if emission is energetically allowed, electron capture is necessarily allowed but not vice−versa.

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For emission of α-particle from uranium nucleus, shortage of two electrons in thorium is due to :92U235−2He4→90Th231

The correct options are C combination with positron to evolve energy D annihilationFor emission of α-particle from uranium nucleus : 92U235−2He4→90Th231Shortage of two electrons in thorium is due to Annihilation. Electron combine with positron to evolve energy.−10e++10e→energy

For emission of $α$ -particle from uranium nucleus, shortage of two electrons in thorium is due to :
$_{92} U^{235} -_{2} H e^{4} \to_{90} T h^{231}$