Question

For energy density, power and intensity of any wave choose the correct options.

• A. $u=energydensity=\frac{1}{2}\rho {\omega }^2{A}^2$
• B. $P=power=\frac{1}{2}\rho {\omega }^2{A}^{2}v$
• C. $I=intensity=\frac{1}{2}\rho {\omega }^2{A}^{2}Sv$
• D. $I=\frac{P}{S}$

Answer 1

The correct option is D $I=\frac{P}{S}$

Energy density of wave $=\frac{Power.dt}{Svdt}=\frac{Intensity}{velocity}$

$power=Intensity\times Areaofcrosssection.$

$I=\frac{1}{2}{\mu w}^2{A}^{2}v$

$I=\frac{P}{Area}$