For every natural number n, n $(n^{2} - 1)$ is divisible by

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None of these

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Solution

The correct option is B
6

n $(n^{2} - 1)$ = (n - 1)(n)(n + 1)

It is product of three consecutive natural

numbers, so according to Langrange's theorem

it is divisible by 3 ! i.e., 6.

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