For every positive integral value of n, $3^{n}$ > $n^{3}$ when

n > 2

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$n\geq$ 3

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$n\geq$ 4

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n < 4

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Solution

The correct option is C
$n\geq$ 4

Check through option, the condition $3^{n}$ > $n^{3}$ is

true when n ≥ 4.

Suggest Corrections

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