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Question

For every real number c0, find all the complex numbers z which satisfy the equation 2|z|4cz+1+ic=0.

A
(x,y)=4c±4c2+34(4c21),1/4
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B
(x,y)=4c±4c2+34(4c2+1),1/4
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C
(x,y)=4c±4c2+34(4c21),1/4
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D
(x,y)=4c±4c2+34(4c2+1),1/4
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Solution

The correct option is A (x,y)=4c±4c2+34(4c21),1/4
Let z=x+iy
2x2+y24c(x+iy)+1+ic=0
Considering the imaginary part, we get
4cy+c=0
y=14
Substituting in the real part, we get
16x2+18cx+2=0

16x2+1=64c2x232cx+4

x2(64c216)32cx+3=0

x=32c±1024c2768c2+1922(64c216)
8c±16c2+122(16c24)
4c±4c2+34(4c21)

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