wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For given penthybrid cross for AaBbCcDdEe how many possible different genotype and phenotype is obtained in F2 generation?

Open in App
Solution

In the self-cross of AaBbCcDdEe X AaBbCcDdEe, there are 5 heterozygous genes. In order to calculate the number of genotypes in F2 generation, the formula used is 3n, where n is the number of heterozygous genes. So, the number of genotypes will be 35= 243.
The number of phenotypes will be 2n, so 25=32.
So, there will be 243 genotypes and 32 phenotypes possible.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Phenotype and Genotype
BIOLOGY
Watch in App
Join BYJU'S Learning Program
CrossIcon