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Question

How many different genotypes and phenotypes are produced in the F2 generation of a dihybrid cross performed by Mendel considering that the parents are true breeding for round, yellow seeds and wrinkled, green seeds?

A
4 - phenotypes
9 - genotypes
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B
4 - phenotypes
16 - genotypes
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C
16- phenotypes
16 - genotypes
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D
4 - genotypes
9 - phenotypes
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Solution

The correct option is A 4 - phenotypes
9 - genotypes
Considering the parents to be pureline of contrasting traits of seed shape and seed colour:
F2 generation:
GametesRYRyrYryRYRRYYRRYyRrYYRrYy(Round, yellow)(Round, yellow)(Round, yellow)(Round, yellow)RyRRYyRRyyRrYyRryy(Round, yellow)(Round, green)(Round, yellow)(Round, green)rYRrYYRrYyrrYYrrYy(Round, yellow)(Round, yellow)(Wrinkled, yellow)(Wrinkled, Yellow)ryRrYyRrYyrrYYrrYy(Round, yellow)(Round, green)(Wrinkled, yellow)(Wrinkled, green)
This will lead to the production of following phenotypes and genotypes:-
Phenotypes:- 4 types
Round yellow : round green : wrinkled yellow : wrinkled green
= 9 : 3 : 3 : 1
PhenotypesNo.of offspringsRound yellow9Round green3Wrinkled yellow3Wrinkled green1
Genotypes:- 9 types
RRYY : RrYY : rrYY : RRYy : RrYy : rrYy : RRyy : Rryy : rryy
= 1 : 2 : 1 : 2 : 4 : 2 : 1 : 2 : 1
GenotypesNo.of offspringsRRYY1RrYY2rrYY1RRYy2RrYy4rrYy2RRyy1Rryy2rryy1

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