For r=0,1,…, 10, let Ar,Br and Cr denote, respectively, the coefficient of xr in the expansions of (1+x)10,(1+x)20 and (1+x)30 Then 10∑r=1Ar(B10Br−C10Ar) is equal to
A
B10−C10
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B
A10(B210−C10A10)
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C
0
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D
C10−B10
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Solution
The correct option is DC10−B10 The given expansion can be written as ∑10r=110Cr(20C10.20Cr−30C10.10Cr) 20C10∑10r=110Cr.20Cr−30C10∑10r=1(10Cr)2 ⇒20C10[30C20−1]−30C10[20C10−1] ⇒30C10−20C10 ⇒C10−B10