For preparing 3.00L of 1MNaOH by mixing portions of two stock solutions (A and B) of 2.50MNaOH and 0.40MNaOH respectively. Find out the amount of B stock solution (in L) added :
A
8.57L
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B
2.14L
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C
1.28L
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D
7.51L
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Solution
The correct option is D2.14L Let x L of B stock solution is added. 3.00−x L of A stock solution will be added. MV=MAVA+MBVB 1.00 M × 3.00 L = 2.50 M × (3.00-x) L+ 0.40 M × x L 3.00=7.50−2.50x+0.40x 4.50=2.10x x=2.14 L