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Question

For preparing 3.00 L of 1M NaOH by mixing portions of two stock solutions (A and B) of 2.50 M NaOH and 0.40 M NaOH respectively. Find out the amount of B stock solution (in L) added :

A
8.57 L
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B
2.14 L
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C
1.28 L
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D
7.51 L
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Solution

The correct option is D 2.14 L
Let x L of B stock solution is added.
3.00x L of A stock solution will be added.
MV=MAVA+MBVB
1.00 M × 3.00 L = 2.50 M × (3.00-x) L+ 0.40 M × x L
3.00=7.502.50x+0.40x
4.50=2.10x
x=2.14 L

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