For r=0,⋯,10,IfAr,Br and Cr denote respectively the coefficient of xr in the expansions of (1+x)10,(1+x)20,and(1+x)30. Then the value of ∑10r=1Ar(B10Br−C10Ar) is
A
B10−C10
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B
A10(B210−c10A10)
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C
\N
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D
C10−B10
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Solution
The correct option is DC10−B10 Ar = Coefficient of xrin(1+x)12=10Cr Br = Coefficient ofxrin(1+x)20=20Cr Cr= Coefficient of xrin(1+x)30=30Cr ∴∑10r=1Ar(B10Br−C10Ar)=∑10r=1ArB10Br−∑10r=1ArC10Ar
=∑10r=110Cr20C1020Cr−∑10r=110Cr30C1010Cr =∑10r=110C10−r20C1020Cr−∑10r=110C10−r30C1010Cr =20C10∑10r=110C10−r.20Cr−30C10∑10r=110C10−r10Cr =20C10(30C10−1)−30C10(20C10−1)=30C10−20C10=C10−B10