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Question

For r=0,1,2,,....10 let Ar,Br and Cr denote respectively the coefficient of xr in the expansions of (1+x)10,(1+x)20 and (1+x)30. Then 10r=1Ar(B10BrC10Ar) is equal to

A
B10C10
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B
A10(B210C10A10)
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C
0
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D
C10B10
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Solution

The correct option is D C10B10
Ar= Coefficient of xr in (1+r)10=10 Cr
Br= Coefficient of xr in (1+r)20=20 Cr
Cr= Coefficient of xr in (1+r)30=30 Cr
10r=1Ar(B10BrC10Ar)=10r=1ArB10Br10r=1ArC10Ar
=10r=1_10Cr_20C10_20Cr10r=1_10Cr_30C10_10Cr
=10r=1_10Cr_20C10_20Cr10r=1_10Cr_30C10_10Cr
=_20C1010r=1_10C10r_20Cr_30C1010r=1_10C10r_10Cr
=20C10(30C101)30C10(20C101)
=30C1020C10=C10B10
C10B10




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