For series L - C - R- graph between peak current and frequency - shown in the figure below- The correct order for R 1- R 2 and R 3Frequency A- R 3- R 1- R 2B- R 3- R 2- R 1- R 1- R 2- R 3D- R 2- R 1- R 3

The correct option is C R_1 gt; R_2 gt; R_3Less is the resistance, less is the impedance and more is the current. nbsp; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Impedance in RLC Circuit

For series L ...

Question

For series $L - C - R$ , graph between peak current and frequency ( $ω$ ) shown in the figure below.
The correct order for $R_{1}, R_{2} a n d R_{3}$

R_{1} > R_{2} > R_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

R_{2} > R_{1} > R_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

R_{3} > R_{1} > R_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

R_{3} > R_{2} > R_{1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

L - C - R

ω

R_{1}, R_{2} a n d R_{3}

△ A B C

a < b < c

r

r_{1}, r_{2}, r_{3}

A, B, C

r < r_{1} < r_{2} < r_{3}

△ A B C, r_{1} r_{2} + r_{2} r_{3} + r_{3} r_{1} = \frac{r_{1} r_{2} r_{3}}{r}

Δ

r_{1} + r_{2} + r_{3} - r = 4 R

r_{1} r_{2} + r_{2} r_{3} + r_{3} r_{1} = Δ^{2}

(a \times 2 a \times 4 a)

R_{1}

R_{2}

R_{3}

Join BYJU'S Learning Program