For silver metal, the threshold frequency (ν0) is 1.12×1017Hz. What is the maximum kinetic energy of the photoelectrons produced by shining UV light of wavelength 15∘A on the metal?
A
3.00×1017J
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B
5.8×10−17J
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C
3.9×10−17J
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D
2×1015J
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Solution
The correct option is B5.8×10−17J We know: ν=cλ=3×108ms−115×10−10m=2×1017s−1(or Hz) Also, K.E=hν−hν0=h(ν−ν0) K.E=6.626×10−34×(2×1017−1.12×1017) K.E=5.8×10−17J