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Question

For sodium acetate solution in water, the given equilibrium reaction occur:
CH3COO (aq)+H2O (l)hydrolysisCH3COOH (aq)+OH (aq)
Which of the following describes the correct relation ?
(where h is the degree of hydrolysis of salt)

A
h=KwCKa
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B
h=KwKaC
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C
h=KaCKw
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D
h=KaKwC
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Solution

The correct option is B h=KwKaC
Salt of weak acid and strong base. If C is the concentration and h is the degree of hydrolysis, then hydrolysis of anion takes place as following :
CH3COOC(1h) (aq)+H2O (l)hydrolysisCH3COOHCh (aq)+OHCh (aq)

Kh=[CH3COOH][OH][CH3COO]=Ch×ChC(1h)=Ch21h
and,
CH3COOHCH3COO+H+Ka=[CH3COO][H+][CH3COOH]H2OH++OHKw=[H+][OH]
We see that
Kh=KwKa=Ch21hFor h<0.1Then, 1h1KwKa=Ch2h=KwKaC

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