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For strong el...

Question

For strong electrolytes, van't Hoff factor 'i' equals to total number of _____ (ions/atoms) in the formula unit.

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Solution

Consider the strong electrolyte $A_{x} B_{y}$ .
It completely dissociates into aqueous solution.

$A_{x} B_{y} \to x A^{+ y} + y B^{- x}$

The total number of ions in the formula unit $= x + y$
The van't Hoff factor $, i = \frac{Actual number of particles}{Number of particles for no ionization} = \frac{x + y}{1} = x + y$
Hence, for strong electrolytes, van't Hoff factor 'i' equals to total number of ions in the formula unit.

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