wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For the arrangement in figure: The elongation in spring in equilibrium condition is [take g =10 m/s2]


A

0.04 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

0.06 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

Can't be predicted

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

0.06 m



FBD of system is as shown in figure.
Limiting value of f1 and f2 are 4N & 6N respectively AS 1×g=fL1+fL2 the system is just on the verge of sliding and friction are limiting in nature
T1=1×g=10 N

Kx+fL1 = T1 kx = 10 - 4 = 6 Ns

So, x = 0.06 m


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon