For the arrangement in figure: The elongation in spring in equilibrium condition is [take $g = 10$ m/s²]

$0.04$ m

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$0.06$ m

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zero

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Can't be predicted

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Solution

The correct option is B
$0.06$ m

FBD of system is as shown in figure.
Limiting value of f₁ and f₂ are 4N & 6N respectively AS 1×g=f_L1+f_L2 the system is just on the verge of sliding and friction are limiting in nature
T₁=1×g=10 N
Kx+f_L1 = T₁ kx = 10 - 4 = 6 Ns

So, x = 0.06 m

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Similar questions

For the arrangement in figure: The elongation in spring in equilibrium condition is [take g =10 m/s²]

g = 10 m / s^{2}

g = 10 m / s^{2}

k g / m^{3}

m / s^{2}

g = 10 {m/s}^{2}

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