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Question

For the arrangement shown in the figure, the tension in the string is given by (sin37=35). Take g=10 ms2


A
30 N
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B
40 N
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C
60 N
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D
30 N
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Solution

The correct option is B 40 N

Net pulling force on the system F=10gsin374g=20 N
maximum force of friction
fmax=μmg cos37
=0.7×10×10×45=56 N
Since F<fmax, system will not move. Equilibrium of 4 kg gives T=40 N.

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