Question

For the beam AB shown in the figure, the fixed end moments at ends A and B will be respectively

• A. -27 kN-m, 18 kN-m
• B. -18 kN-m, 27 kN-m
• C. 18 kN-m, 27 kN-m
• D. 27 kN-m, -18 kN-m

Answer 1

The correct option is B -18 kN-m, 27 kN-m

$M{F}_{AB}=(-)\frac{w{l}^2}{30}=(-)\frac{15\times 36}{30}=-18kN-m$

$M{F}_{BA}=(+)\frac{w{l}^2}{20}=(+)\frac{15\times 36}{20}=27kN-m$