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Byju's Answer
Standard IX
Physics
Work-Done and Power
For the block...
Question
For the block diagrm shown in figure, the transfor function
C
(
s
)
R
(
s
)
is equal to
A
s
2
+
1
s
2
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B
s
2
+
s
+
1
s
2
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C
s
2
+
s
+
1
s
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D
1
s
2
+
s
+
1
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Solution
The correct option is
B
s
2
+
s
+
1
s
2
Method -1:
Using block-diagram redius technique.
So, transfer function
C
(
s
)
R
(
s
)
=
s
2
+
s
+
1
s
2
Method -2:
using signal flow graph
Thre forward paths,
P
1
=
1
s
.
1
s
=
1
s
2
,
P
2
=
1
s
a
n
d
P
3
=
1
The number of individual loop = 0
So graph determinant
Δ
=
1
a
n
d
Δ
1
=
Δ
2
=
Δ
3
=
1
Applying Mason's gain formula
G
(
s
)
=
C
(
s
)
R
(
s
)
=
P
1
Δ
1
+
P
2
Δ
2
+
P
3
Δ
3
Δ
S
2
.1
+
1
s
.1
+
1.1
1
=
s
2
+
s
+
1
s
2
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