Question

For the circuit arrangement shown in figure, the charge on the capacitor in the steady state condition is

• A. $12\mu C$
• B. $14\mu C$
• C. $20\mu C$
• D. $18\mu C$

Answer 1

The correct option is D $18\mu C$

In the steady state, current through the branch containing the capacitor is zero. Hence, current through battery is



$I=\frac{12}{6+2}=\frac{3}{2}A$

Potential difference across the capacitor,

$V_{AB}=6\times \frac{3}{2}=9V$

$\therefore q=C{V}_{AB}=2\times 9=18\mu C$