Question

For the circuit shown below
Power delivered by 7 A current source is

• A. 37.31 W
• B. 51.31 W
• C. 21.31 W
• D. 31.31 W

Answer 1

The correct option is A 37.31 W

Applying KCL to supernode

$2=i_1+i_2+7$
$2=\frac{V_1}{2}+\frac{V_2}{4}+7$
$8=2V_1+V_2+28$
$\Rightarrow 2V_1+V_2=-\mathrm{20...}\left(i\right)$
$V_2-V_1=\mathrm{2..}\left(ii\right)$
After solving (i) and (ii),
$V_1=-7.33V$
$V_2=-5.33V$
Power delivered by 7 A current source
$=5.33\times 7$
$=37.31W$