Question

For the circuit shown below the steady- state current is

• A. 0 A
• B. $5\sqrt{2}cos\left(1000t\right)A$
• C. $5\sqrt{2}cos(1000t-\frac{\pi }{4})A$
• D. $5\sqrt{2}A$

Answer 1

The correct option is A 0 A


$Z_c=\frac{1}{j\omega C}=\frac{1}{j\times 1000\times {10}^{-3}}=-j$

$Z_L=j\omega L=j\times 1000\times {10}^{-3}$

$=j$

$\therefore Z_{eq}=1+\frac{-j\times j}{-j+j}$

$Z_{eq}\to \infty$

The current in the given circuit will be zero.