CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

RLC Circuit

For the circu...

Question

For the circuit shown, find the potential difference across the inductor.

Open in App

Solution

Impedance across $A B = Z_{1}$
$X_{C} = - \frac{j}{C ω} = - j \times \frac{1}{100 \times 10^{- 6} \times 200} = 50 (- j)$
$Z_{1} = X_{C} ∥ R_{1} = \frac{50 \times 50 (- j)}{50 - 50 j} = \frac{- 50 j}{1 - j} = - 25 (1 + j) j = 25 (1 - j) = 25 - 25 j$
Total impedance $Z = X_{L} + Z_{1} + R_{2} = j ω L + Z_{1} + R_{2} = j 200 \times 0.325 + 25 - 25 j + 5 = j 65 + 25 - 25 j + 5 = 30 + 40 j$
$| Z | = 50$ $Ω$
Voltage across inductor $V_{L} = \frac{V}{Z} \times X_{L}$
$| V_{L} | = \frac{60}{50} \times 65 = 78$ $V$

Suggest Corrections

thumbs-up

0

Similar questions

I

, potential difference

V_{L}

across the inductor and potential difference

V_{C}

across the capacitor in circuit as shown in the figure are best represented vectorially as

LR

AC

source has voltage

220 V

. If the potential difference across the inductor is

176 V

, the potential difference across the resistor will be

Q. In a series LCR circuit, what is the phase difference between

V_{L}

V_{C}

V_{L}

is the potential difference across the inductor and

V_{C}

is the potential difference across the capacitor ?

Q. In a series LCR circuit, resonance occurring at 105Hz. At that time, the potential difference across the 100 resistance is 40V while the potential difference across the pure inductor is 30v. The inductance L of the inductor is equal to

L C R

circuit is connected to a source of alternating emf

50 V

and if the potential differences across inductor and capacitor are

90 V

60 V

respectively, the potential difference across resistor is:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Series RLC

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon