For the circuit shown in figure, the current i0 is
A
-0.4705 A
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B
8.4705 A
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C
3.4705 A
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D
-2.3705 A
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Solution
The correct option is A -0.4705 A
Apply mesh analysis, i1=4 i0=(i1−i3)=4−i3 3(i2−i1)+2i2−5i0+(i2−i3)=0 6i2+4i3=32...(i) 1(i3−i2)+5i0+4i3−20−5i0=0 5i3−i2=20...(ii)
From equation (i) and (ii), we get i2=2.35A; i3=4.4705A i0=4−i3=−0.4705A