Question

For the circuit shown in figure, the current $i_0$ is

• A. -0.4705 A
• B. 8.4705 A
• C. 3.4705 A
• D. -2.3705 A

Answer 1

The correct option is A -0.4705 A


Apply mesh analysis,
$i_1=4$
$i_0=(i_1-i_3)=4-i_3$
$3(i_2-i_1)+2i_2-5i_0+(i_2-i_3)=0$
$6i_2+4i_3=\mathrm{32...}\left(i\right)$
$1(i_3-i_2)+5i_0+4i_3-20-5i_0=0$
$5i_3-i_2=\mathrm{20...}\left(ii\right)$
From equation (i) and (ii), we get
$i_2=2.35A;$
$i_3=4.4705A$
$i_0=4-i_3=-0.4705A$