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Standard XII

Physics

Electrical Oscillations

For the circu...

Question

For the circuit shown in the figure, find the charge stored on capacitor in steady state.

\frac{R C}{R + R_{0}} E

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\frac{R C}{R_{0}} (E - E_{0})

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zero

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\frac{R C}{R + R_{0}} (E - E_{0})

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Solution

The correct option is B $\frac{R C}{R + R_{0}} (E - E_{0})$
In steady-state, the capacitor is fully charged so no current flows in the capacitor branch.
Now using ohm's law , $E - E_{0} = i (R + R_{0})$
$\Rightarrow i = \frac{E - E_{0}}{R + R_{0}}$

Potential across capacitor is:
$V_{a} - V_{b} = E - E + i R = i R$

$\Rightarrow \frac{E - E_{0}}{R + R_{0}} R$

$∴$ Charge on capacitor $= C (V_{a} - V_{b}) = \frac{(E - E_{0}) R C}{R + R_{0}}$

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For the circuit shown in the figure, find the charge stored on capacitor in steady state.

The correct option is B RCR+R0(E−E0)In steady-state, the capacitor is fully charged so no current flows in the capacitor branch.Now using ohm's law , E−E0=i(R+R0)⇒i=E−E0R+R0Potential across capacitor is: Va−Vb=E−E+iR=iR⇒E−E0R+R0R∴ Charge on capacitor =C(Va−Vb)=(E−E0)RCR+R0