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Question

# For the circuit shown in the figure, initially the switch is closed for a long time so that steady state has been reached. Then at t=0, the switch is opened, due to which current in the circuit decays to zero. The heat generated in the inductor is [L = self inductance of inductor, r = resistance of inductor] :

A

zero

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B

E22(R+r)

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C

E2L2r(R+r)

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D

E2R2r(R+r)

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Solution

## The correct option is C E2L2r(R+r) Let heat generated in inductor be H1 and in R be H2 then : Total Heat generated H1+H2=12L×(Er)2=E2L2r2..........(1) Ratio of Heat generated H1H2=rR...............(2) from (1) & (2) H1+H1Rr=E2L2r2 H1=E2L2r(r+R)

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