CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Switch S is closed at t=0, in the circuit shown. The change in flux in the inductor (L=500mH) from t=0 to an instant when it reaches steady state is :

215188.PNG

A
2 Wb
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.5 Wb
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0 Wb
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1.5 Wb
Before closing the switch, inductor acts as a short circuit as it is in steady state.
Hence, Initial current Ii=1010=1A
Initial flux, ϕi=L(Ii)=500mWb
=0.5Wb
At steady state,
Final current If=205=4A
Final flux, ϕf=L(If)=(0.5)×4=2Wb
Δϕ=1.5Wb

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Series RLC
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon