Question

For the circuit shown in the figure, the Thevenin voltage and resistance looking into X-Y are

• A. 4/3 V, 2$\Omega$
• B. 4 V, 2/3$\Omega$
• C. 4/3 V, 2/3$\Omega$
• D. 4 V, 2$\Omega$

Answer 1

The correct option is D 4 V, 2$\Omega$

For V${}_{Th}$, applying KCL at node X

$2=\frac{V_{Th}}{2}+\frac{V_{Th}}{1}+\frac{V_{Th}-2i}{1}$

$where,i=\frac{V_{Th}}{1}$

$So,2=V_{Th}(\frac{1}{2}+\frac{1}{1}+\frac{1}{1}-\frac{2}{1})$

$V_{Th}=4volt$

From the figure,
$I_{sc}=2Amp$

$So,R_{Th}=\frac{V_{Th}}{I_{sc}}=\frac{4}{2}$ = 2$\Omega$